How To Create License Key For A Software In Vb6 Array Split Javascript

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I want to take all values from that select statement given below into an array in form1(std exe vb 6.0) and i want to call one function from different form2(activeX dll) and pass these arrays as.

I'm having some trouble populating an array using a split command. The string I currently have is below MyString = 'Row1 Column1[~]Row1 Column2[~]Row1 Column3' & vbNewLine & _ 'Row2 Column1[~]Row2 Column2[~]Row2 Column3' & vbNewLine & _ 'Row3 Column1[~]Row3 Column2[~]Row3 Column3' & vbNewLine & _ 'Row4 Column1[~]Row4 Column2[~]Row4 Column3' I have an array that I want to be multi-dimensional and would like each Row# Column# to be in the correct part of the array based on its number. You can't use Split() on anything other than a String, or a Variant containing a String. If you want to generate a two dimensional string array, you will have iterate through the array returned by Split(), and run Split() on each string.

The following function should do what you want: Private Function SplitTo2DArray(ByRef the_sValue As String, ByRef the_sRowSep As String, ByRef the_sColSep As String) As String() Dim vasValue As Variant Dim nUBoundValue As Long Dim avasCells() As Variant Dim nRowIndex As Long Dim nMaxUBoundCells As Long Dim nUBoundCells As Long Dim asCells() As String Dim nColumnIndex As Long ' Split up the table value by rows, get the number of rows, and dim a new array of Variants. VasValue = Split(the_sValue, the_sRowSep) nUBoundValue = UBound(vasValue) ReDim avasCells(0 To nUBoundValue) ' Iterate through each row, and split it into columns. Find the maximum number of columns.

NMaxUBoundCells = 0 For nRowIndex = 0 To nUBoundValue avasCells(nRowIndex) = Split(vasValue(nRowIndex), the_sColSep) nUBoundCells = UBound(avasCells(nRowIndex)) If nUBoundCells > nMaxUBoundCells Then nMaxUBoundCells = nUBoundCells End If Next nRowIndex ' Create a 2D string array to contain the data in. ReDim asCells(0 To nUBoundValue, 0 To nMaxUBoundCells) ' Copy all the data from avasCells() to asCells(). For nRowIndex = 0 To nUBoundValue For nColumnIndex = 0 To UBound(avasCells(nRowIndex)) asCells(nRowIndex, nColumnIndex) = avasCells(nRowIndex)(nColumnIndex) Next nColumnIndex Next nRowIndex SplitTo2DArray = asCells() End Function Example: Dim asCells() As String asCells() = SplitTo2DArray(MyString, vbNewline, '~'). Here is another approach based on the Variant type's ability to contain an array. Instead of a 2D array we have an 'array of arrays.'

Introduction A string is a sequence of one or more characters that may consist of letters, numbers, or symbols. Each character in a JavaScript string can be accessed by an index number, and all strings have methods and properties available to them. In this tutorial, we will learn the difference between string primitives and the String object, how strings are indexed, how to access characters in a string, and common properties and methods used on strings. String Primitives and String Objects First, we will clarify the two types of strings. JavaScript differentiates between the string primitive, an immutable datatype, and the String object.

In order to test the difference between the two, we will initialize a string primitive and a string object. // Initializing a new string primitive const stringPrimitive = 'A new string.'

; // Initializing a new String object const stringObject = new String('A new string.' ); We can use the typeof operator to determine the type of a value.

In the first example, we simply assigned a string to a variable. Typeof stringPrimitive.

Outputobject Most of the time you will be creating string primitives. JavaScript is able to access and utilize the built-in properties and methods of the String object wrapper without actually changing the string primitive you've created into an object. While this concept is a bit challenging at first, you should be aware of the distinction between primitive and object. Essentially, there are methods and properties available to all strings, and in the background JavaScript will perform a conversion to object and back to primitive every time a method or property is called. How Strings are Indexed Each of the characters in a string correspond to an index number, starting with 0. To demonstrate, we will create a string with the value How are you?